0=3x^2+58x-1400

Solution for 0=3x^2+58x-1400 equation:

0=3x^2+58x-1400

We move all terms to the left:

0-(3x^2+58x-1400)=0

We add all the numbers together, and all the variables

-(3x^2+58x-1400)=0

We get rid of parentheses

-3x^2-58x+1400=0

a = -3; b = -58; c = +1400;
Δ = b2-4ac
Δ = -582-4·(-3)·1400
Δ = 20164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20164}=142$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-58)-142}{2*-3}=\frac{-84}{-6}
=+14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-58)+142}{2*-3}=\frac{200}{-6}
=-33+1/3
$